Math 252 Lecture 26: Friday, March 5th 1999.

Students needed more time for homework assignment #06, so the deadline was extended until Monady.

Irrotational Fields were defined [Transparancy 1] as fields which have a curl of zero everywhere. If F is a conservative field, it will automatically be irrotational because the curl of the grad of any scalar field is zero.

Is the converse true? That is, if a field is irrotational, is it necessarily conservative? It turns out that the converse is only partially true, as given by a theorem which holds only for simply connected domains.

This theorem was proved in the lecture [Transparancies 2 and 3] for the case in which a vector field is defined throughout all space. The proof involves assuming the vector field has a curl of zero, defining a scalar field, and showing that the vector field is the gradient of this scalar field.

An example was considered [Transparancy 4], in which a vector field is irrotational (the curl of F is zero), and yet the field is not conservative. The reason is because the domain is not simply-connected and the theorem applies only to simply-connected domains.

Here are the scanned-in transparancies, in full-colour JPEG format:

(You will find two versions -- a "screen" version, which is 400 pixels wide and a corresponding number of pixels long, at a resolution of 100 by 100 dots per inch, and a "print" version, which is generally between 8 and 8.5 inches wide and up to 11 inches long, also at a resolution of 100 by 100 dots per inch. The screen versions generally have a file size of between 60 and 75 K, which downloads reltively quickly. The print versions generally have a file size of between 170 and 225 K, which takes a bit longer to download.)


SFU / Math & Stats / ~hebron / math252 / lec_notes / lec26 / index.html

Revised 08 March 1999 by John Hebron.